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I didn t even give her a chance to respond; I was now sweating badly and having trouble keeping my right leg from bouncing on the floor, which is what I always do when I am nervous Scott didn t say anything about the way I hung up with my wife I clicked on the trading software and up popped my account I looked at the current profit on the open trade: Three hundred dollars Three hundred dollars! Scott s jaw dropped down My sweat turned cold I heard my heart beating, and my foot stopped drumming on the floor I think 10 seconds passed, but to Scott and me time had ceased to have meaning, and I cascaded into a deep trance I imagined quitting my job that day.

By the algorithm, no points on such segments can be chosen as intermediate targets Ti which means that if the point C is in the main semiplane, then the line segments |CTi | and |Hj T | never intersect Situations that fall into the case in question can in turn be divided into three groups: 3a Point C is located on the obstacle boundary, and C = Ti This happens when the robot walks along a locally convex obstacle boundary (point C , Figure 318) Consider the curvilinear triangle Xj C Q Continuing the boundary segment (Xj C ) after the point C , the obstacle (and the corresponding segment of the Bug2 path) will either curve inside the triangle, with |QT| lying outside the triangle (Figure 318a), or curve outside the triangle, leaving |QT| inside (Figure 318b).

// adjust for rounding mode // - if rounding away from infinity, then we end up at largest value assign oFPSum = ((ExpOutS5 == 8 hff) & !iSNaNS5 & (RModeS5 == ROUNDEVEN )) {SignS5, INF } : ((ExpOutS5 == 8 hff) & !iSNaNS5 & (RModeS5 == ROUNDZERO )) {SignS5, LARGESTVAL } : ((ExpOutS5 == 8 hff) & !iSNaNS5 & (RModeS5 == ROUNDUP ) & !SignS5) {1 b0, INF } : ((ExpOutS5 == 8 hff) & !iSNaNS5 & (RModeS5 == ROUNDUP ) & SignS5) {1 b1, LARGESTVAL } : ((ExpOutS5 == 8 hff) & !iSNaNS5 & (RModeS5 == ROUNDDOWN ) & !SignS5) {1 b0, LARGESTVAL } : ((ExpOutS5 == 8 hff) & !iSNaNS5 & (RModeS5 == ROUNDDOWN ) & SignS5) {1 b1, INF } : ((ExpOutS5 == 8 hff) && iSNaNS5) {SignS5, ExpOutS5, 1 b1, ManS5Out[21:0]} : {SignS5, ExpOutS5 + (coS5 & (ManS5Out == ManS5p1)), ManS5Out}; // adjust exponent if there is a carry over // overflow if we reached our maximum value assign oOverflowAdd = ((oFPSum[30:0] == LARGESTVAL) & ({ExpOutS5, ManS5Out} != LARGESTVAL) ); // inexact also if there is overflow or if there are truncated bits assign oIneAdd = IneAddS5 | oOverflowAdd | (|ManS5[24:0]);

Since the obstacle can cross neither the line |C Q| nor the boundary segment (Xj C ), it (and the corresponding segment of the Bug2 path) must eventually intersect the M-line somewhere between Xj and Q before intersecting |QT| The rest of the argument is identical to case 2 above 3b Point C is on the obstacle boundary, and C = Ti (Figure 318) Consider the curvilinear triangle Xj CQ Again, the obstacle can cross neither the line of.

I could see my wife driving a new sporty sedan, the kids happily cheering her on as she sped through the EZpass gate on the way to our summer home in the Hamptons; then I could see myself diving into an oval of midnight blue water, with reggae music playing in the background and leggy blondes sunning themselves around the edges of the pool This was the life! Trading had brought it to me!.

S (a) (b)

// number of times to shift mantissa if result is subnormal assign ShiftSubNormalS2 = ExpS2 + (ExpS2 == 0); // shift at least once // Rounding conditions to subtract 1 from result assign RoundAdjS2 = ((RModeS2 == ROUNDZERO ) & IneAddS2 & SubS2 & ManZeroS2) | ((RModeS2 == ROUNDDOWN ) & IneAddS2 & !Sign1S2 & SubS2 & ManZeroS2) | ((RModeS2 == ROUNDUP ) & IneAddS2 & Sign1S2 & SubS2 & ManZeroS2); // pre-normalize second operator so that decimals are aligned PreNormAdd PreNormAdd (.iPreShift(Man2), .iShiftVal(ShiftVal), .oPostShift(Man2Shifted), .oIneAdd(IneAddS0)); // normalize result by shifting mantissa and adjusting // exponent by NormShifted PostNormAdd PostNormAdd (.iMantissa(ManS2), .oMantissaNorm(ManS2Norm), .oNormShifted(NormShiftedS2)); // normalization if result is sub normal NormSubNormalAdd NSNA (.iPreShift(ManS2), .oPostShift(ManS2SubnormalNorm), .iShiftVal(ShiftSubNormalS2)); always @(posedge iClk) begin // Stage 0 // First FP must be bigger than the second // if not, then swap the two if(iFP1[30:0] > iFP2[30:0]) begin FP1Adj <= iFP1; FP2Adj <= iFP2; SwapS0 <= 0; end else begin FP1Adj <= iFP2; FP2Adj <= iFP1; SwapS0 <= 1; end ShiftValNoSwapS0 <= iFP1[30:23]-iFP2[30:23] ((iFP2[30:23] == 0) & (iFP1[30:23] != 0));